It isn't anything if the exponent on that denominator is really "x"! If it was supposed to be "2", I recommend dividing the fraction our so that you have a polynomial plus a "proper fraction" of the form [tex]\frac{ax+ b}{x^2+ 1}[/tex]. That you divide into two parts: [tex]\frac{ax}{x^2+1}[/tex] and [tex]\frac{1}{x^2+ 1}[/tex]. The first uses the simple substitution [tex]u= x^2+ 1[/tex] and the second is an arctan.