How can I solve a complex conjugate problem for my friend in college algebra?

AI Thread Summary
To solve the complex conjugate problem {9 - 11i / 6i}, the correct approach involves multiplying both the numerator and denominator by the conjugate of the denominator. The initial attempt yielded -11/6 + 3i/2, but it was clarified that the correct result for the imaginary part is -3i/2. The final answer in standard form is -11/6 - 3i/2. This highlights the importance of careful calculation when working with complex numbers.
camilus
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Homework Statement


sun, I don't know why I am stuggling with a simple freakin problem. Its not even for me its for my friend who's in college algebra, but for some reaon I can't get the correct answer.

{9 - 11i \over 6i}

The Attempt at a Solution


I multiplied by the conjugate twice and got -11/6 + 3i/2
 
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camilus said:

Homework Statement


sun, I don't know why I am stuggling with a simple freakin problem. Its not even for me its for my friend who's in college algebra, but for some reaon I can't get the correct answer.

{9 - 11i \over 6i}

The Attempt at a Solution


I multiplied by the conjugate twice and got -11/6 + 3i/2

What is it exactly that your trying to find?
 
find the quotient and express your answer in standard form.
 
camilus said:
{9 - 11i \over 6i}

The Attempt at a Solution


I multiplied by the conjugate twice and got -11/6 + 3i/2

Hi camilus! :smile:

(you mean "I multiplied both top and bottom by the conjugate" :wink:)

-11/6 is right. :smile:

3i/2 isn't. :cry:
 
thanks tim, I got the answer already. its -3i/2.
 
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