How Can I Solve These Physics Problems on Motion and Acceleration?

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To solve the physics problems on motion and acceleration, the first problem involves determining the acceleration required for a second car to meet a first car traveling at a constant speed of 27 m/s over a distance of 1.8 km. The second problem requires calculating the time it takes for a woman running at 5.0 m/s to catch a bus that accelerates from rest at 1.0 m/s², starting 11 meters away. Initial attempts to solve these problems included visual aids and equations of motion, but the results were incorrect. The first problem's acceleration was estimated at 0.405 m/s², while the time for the second problem was calculated as 1.86 seconds. Further clarification and assistance on the calculations are requested to achieve accurate solutions.
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I can't seem to figure these problems if anyone can give me the concept and start me off that would be great.

Thanks in advance

Problem one: A car is traveling at a constant speed of 27 m/s on a highway. At the instant this car passes an entrance ramp, a second car enters the highway from the ramp. The second car starts from rest and has a constant acceleration. What acceleration must it maintain so that the two cars meet for the first time at the next exit which is 1.8 km away?

Problem two: A bus stop to pick up riders. A woman is running at a constant velocity of +5.0 m/s in an attempt to catch the bus When she is 11 m from the bus, it pulls away with a constant acceleration of +1.0 m/s^2. From this point, how much time does it take her to reach the bus if she keeps running with the same velocity?

*edit* oh and let me show you what i did so far

ok for problem one i drew a picture to visualize this and somehow came up with .405 m/s^2. I think what i did was found out the time it took to get to 1800 m with 27 m/s as its velocity and got seconds and after i did 27/66.7(which was the result from what i did previously)

with problem two i did: x=Vot+1/2at^2

and got 1.86 s which i know is wrong =(

any help would be fine thanks
 
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Oh i replied to you in the other forum.
 
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