John999
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I'm having problems solving this differential equation:
x*dy/dx-2*y=(x^2)*cos(x)
y(pi/2)=0
Thanks
x*dy/dx-2*y=(x^2)*cos(x)
y(pi/2)=0
Thanks
Can one think of a way that xy'-2y looks like the derivative of a quotient?John999 said:I'm having problems solving this differential equation:
x*dy/dx-2*y=(x^2)*cos(x)
y(pi/2)=0
Thanks
John999 said:I'm having problems solving this differential equation:
x*dy/dx-2*y=(x^2)*cos(x)
y(pi/2)=0
Thanks