How can we calculate the current (I) if we have cable with 25 mm size for 480V?

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To calculate the current (I) for a 25 mm² cable at 480V, it is essential to consider the load being supplied rather than the cable size alone. The maximum current capacity, or ampacity, of the cable depends on its cross-sectional area and insulation type, which can be referenced from ampacity charts. Additionally, the cable's insulation must be rated for the voltage to prevent arcing. Users should also consider voltage drop and current control in their calculations. Proper selection of cable based on load and safety ratings is crucial for effective plant project implementation.
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dear engineer,

how can we calculate the current (I) if we have cable with 25 mm size for 480V?
and are there any other parameters we should know to calculate the current.


(for plant project purpose)
 
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Are you asking what the maximum safe current is for this size of cable, or asking how much current you have when you short out 480V with a segment of this cable?

If you're asking how much current is carried to a load when using a 480V supply, this is determined chiefly by the load, and not the cable (though clearly, you need to ensure that the cable can carry that current, otherwise you'll just have burnt / melted cable)
 
thanx MATLABdude, you are right the cable should be chosen by considering the load and the current carried to the load.
however what I meant is the maximum current appropriate for this size of cable.
 
megatronic said:
thanx MATLABdude, you are right the cable should be chosen by considering the load and the current carried to the load.
however what I meant is the maximum current appropriate for this size of cable.

Is 25 mm the diameter or do you mean 25 mm^2 for the cross-sectional area?

CS
 
stewartcs said:
Is 25 mm the diameter or do you mean 25 mm^2 for the cross-sectional area?

CS

the cross section 25mm^2
 
That sounds like it's somewhere between 3 and 4 AWG cable:
http://en.wikipedia.org/wiki/American_wire_gauge

The ampacities are listed for various insulator temperature ratings. You also need to ensure that the jacket is rated for the voltage that it's carrying (otherwise, you might have arcing through the insulation between cables lying side by side).
 
thanx MATLABdude the link will be useful
 
visit this site.
Simply and quickly..

http://www.incable.somee.com

calculating drop-voltage, current control
 
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