Misr said:
[PLAIN]http://media.tiscali.co.uk/images/feeds/hutchinson/ency/osci0001.jpg
I don't understand the concept of a complete osillation perfectly..I see that the vibrating object passes through the rest position two times in two different diection??How does the object have the same phase relative to the rest position..
Thanks in advance
When I teach this, I stand at the board with a marker in my mark and move my hand up and down regularly. This makes a dark mark on the board. Then, while still raising and lowering the marker, I walk parallel to the board. The marker traces out a sine wave. Can you picture that?
In the same way, a marker attached to the pendulum would trace out a sine wave on a piece of paper that moved under it. This
http://www.youtube.com/watch?v=MhG5UceWxLk" sort of gets the idea across, especially if you imagine the pen moving as smoothly as a pendulum.
I think the answer to your question is clear if you focus on the sine wave associated with the pendulum movement. In the situation drawn on the left side of the diagram you posted, the wave would start at a crest at A, pass through the axis, be at a trough at B. cross the axis again and end at a crest at A. That would be one complete oscillation and one complete wavelength (being crest to to descending node to trough to ascending node to crest).
In the the situation drawn on the right, you start at the axis at A, go to the crest at B, back through the axis (A), to the trough at C and once more to the axis at A. That again is one wavelength (ascending node to crest to descending node to trough to ascending node).
Does that answer your question?