How Can y(x) Be Expressed as a Convolution in This Differential Equation?

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To express y(x) as a convolution in the given differential equation, start by multiplying both sides by the exponential e^{ax}. This allows the left side to be rewritten as a single derivative using the product rule. The key is to recognize that the resulting expression can be integrated to find y(x) in terms of f(x) and the exponential function. Understanding this relationship is crucial for deriving the convolution form. Further exploration of the integration process will lead to the desired expression for y(x).
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Any hints to this problem?

"Assume the solution to a differential equation is given by
\frac{dy(x)}{dx}+ay(x) = f(x)
where y(0)=y_0 and a is a constant. Show how y(x) can be written as a convolution of f(x) and an exponential e^{ax}."

The only hint we got from the prof was to multiply both sides by the exponential and express the left as a single term, but I could be doing something wrong there as well. Anyone have any more hints? (I don't want the solution just yet, I just want to try to work it out first)

Thanks
 
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Upon multiplying both sides with the exponential, recall next that
\frac{d(uv)}{dx} = u\frac{dv}{dx} + v\frac{du}{dx}
 

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