How Can You Calculate the Altitude of a Satellite Using Gravitational Equations?

  • Thread starter Thread starter chewtoy929
  • Start date Start date
  • Tags Tags
    Class
AI Thread Summary
To calculate the altitude of a satellite, use gravitational equations that relate gravitational force to mass and distance. The relevant formulas include F_g = GMm/r^2 and mg = GMm/r^2, where G is the gravitational constant. It's important to note that for satellites at significant altitudes, the acceleration due to gravity (g) is not 9.81 m/s^2, but rather varies with distance from the Earth's center. By substituting the known values into these equations and solving for r, one can determine the satellite's distance from the Earth's center and subsequently its altitude. This approach effectively combines gravitational potential energy and acceleration to find the required altitude.
chewtoy929
Messages
10
Reaction score
0
how can I calculate the distance something is above the earth? as an example a 1750 kg satellite orbits the earth. it has a gravitational potential energy of 1.69*10^10 J. Its free fall accel is 6.44 m/s^2 how high is it.

How would I solve this? thanks.
 
Physics news on Phys.org
Thread movdd to Homework Help forums.

Welcome to the PF, chewtoy. On homework and coursework questions, you must show us the relevant equations and also your initial attempt at a solution, before we can offer much in the way of tutorial help.

You appear to be studying uniform circular motion and gravitational forces. Show us the relevant equations from your textbook for this subject matter, and tell us your thoughts on how you might use those equations to approach this question.
 
Use this formula :

F_g = GMm/r^2

or

mg = GMm/r^2
 
tnutty said:
Use this formula :

F_g = GMm/r^2

or

mg = GMm/r^2

dont you mean use a = GM/R^2? If a satellite is way above Earth's surface, using little g(9.81) for any calculation would be wrong. the point of that equation is the gravitational pull ISN'T 9.81.

the force one mass pulls on the other mass is equal to gravitational constant 6.67...something * mass of object 1 * mass of object 2 divided by the distance from the centers of the objects squared:
GMm/r^2 = F

you know by now that f = ma

substitute for f, use your given a, and solve for r.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top