How Can You Calculate the Magnitude of the Force of Friction on a Slide?

AI Thread Summary
To calculate the magnitude of the force of friction on a slide, first determine the speed of a 51.1 kg thrill seeker at the bottom without friction, which is 26.5 m/s. When accounting for friction, if the thrill seeker reaches a speed of 22.6 m/s, the change in mechanical energy due to friction is -4978 J. The normal force is calculated as 354 N, but the coefficient of friction (mu) is not directly provided. The key to finding the force of friction lies in using the work-energy principle, where the work done against friction equals the energy lost. The discussion emphasizes a backward approach to solving the problem when direct calculations are challenging.
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Homework Statement



Suppose a slide similar to Der Stuka is 36.0 meters high, but is a straight slope, inclined at 45° with respect to the horizontal.
(a) Find the speed of a 51.1 kg thrill seeker at the bottom of the slide, assuming no friction.
26.5 m/s

(b) If the thrill seeker has a speed of 22.6 m/s at the bottom, find the change in mechanical energy due to friction.
-4978 J

(c) Find the magnitude of the force of friction, assumed constant.
____ N2. Homework Equations /attempts
Magnitude of F = W/change in X, but no X is given, just Y.
I know F= mu/N and I found normal force to be [51.1 kg*9.8 m/s^2 cos(45)]=354 N

I am stuck there and cannot think of a way to calculate mu.
 
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septum said:

Homework Statement



Suppose a slide similar to Der Stuka is 36.0 meters high, but is a straight slope, inclined at 45° with respect to the horizontal.
(a) Find the speed of a 51.1 kg thrill seeker at the bottom of the slide, assuming no friction.
26.5 m/s

(b) If the thrill seeker has a speed of 22.6 m/s at the bottom, find the change in mechanical energy due to friction.
-4978 J

(c) Find the magnitude of the force of friction, assumed constant.
____ N


2. Homework Equations /attempts
Magnitude of F = W/change in X, but no X is given, just Y.
I know F= mu/N and I found normal force to be [51.1 kg*9.8 m/s^2 cos(45)]=354 N

I am stuck there and cannot think of a way to calculate mu.

You know how fast he was going frictionless. Now they tell you how fast he was going under less than ideal conditions. i.e with friction.

The difference in speed then must have been from the friction. So what was the retarding force, given by first determining the difference from ideal acceleration?
 
I still don't get this at all.
 
You aren't given the coefficient of friction, so you can't work it out with F = uN.
Work with the energy lost due to friction, which you do have from part (b).
This is the work done against the force of friction, W = F*d.
 
I... finally came to the answer after about 8 pieces of paper. I think far too into this. Thank you for your help
 
Speed will come with experience! The lesson on this one is that if you can't work forwards, try working backwards.
 
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