How Can You Calculate the Magnitude of the Force of Friction on a Slide?

Click For Summary

Homework Help Overview

The discussion revolves around calculating the magnitude of the force of friction on a slide, specifically a scenario involving a thrill seeker descending a 36.0-meter high slide inclined at 45°. Participants explore the relationship between speed, mechanical energy, and friction.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the initial conditions of the problem, including the speed of the thrill seeker under frictionless conditions and the observed speed with friction. There are attempts to relate the change in mechanical energy to the force of friction, with some questioning how to calculate the coefficient of friction without direct information.

Discussion Status

The discussion has seen various attempts to connect the concepts of energy loss due to friction with the force of friction itself. Some participants have suggested focusing on the energy lost as a means to approach the problem, while others express confusion about the calculations involved. There is no explicit consensus, but guidance has been offered regarding the use of energy concepts.

Contextual Notes

Participants note the absence of the coefficient of friction and the lack of distance information, which complicates the calculation of the force of friction. The problem is framed within the constraints of a homework assignment, emphasizing the need to work with given data.

septum
Messages
10
Reaction score
0

Homework Statement



Suppose a slide similar to Der Stuka is 36.0 meters high, but is a straight slope, inclined at 45° with respect to the horizontal.
(a) Find the speed of a 51.1 kg thrill seeker at the bottom of the slide, assuming no friction.
26.5 m/s

(b) If the thrill seeker has a speed of 22.6 m/s at the bottom, find the change in mechanical energy due to friction.
-4978 J

(c) Find the magnitude of the force of friction, assumed constant.
____ N2. Homework Equations /attempts
Magnitude of F = W/change in X, but no X is given, just Y.
I know F= mu/N and I found normal force to be [51.1 kg*9.8 m/s^2 cos(45)]=354 N

I am stuck there and cannot think of a way to calculate mu.
 
Physics news on Phys.org
septum said:

Homework Statement



Suppose a slide similar to Der Stuka is 36.0 meters high, but is a straight slope, inclined at 45° with respect to the horizontal.
(a) Find the speed of a 51.1 kg thrill seeker at the bottom of the slide, assuming no friction.
26.5 m/s

(b) If the thrill seeker has a speed of 22.6 m/s at the bottom, find the change in mechanical energy due to friction.
-4978 J

(c) Find the magnitude of the force of friction, assumed constant.
____ N


2. Homework Equations /attempts
Magnitude of F = W/change in X, but no X is given, just Y.
I know F= mu/N and I found normal force to be [51.1 kg*9.8 m/s^2 cos(45)]=354 N

I am stuck there and cannot think of a way to calculate mu.

You know how fast he was going frictionless. Now they tell you how fast he was going under less than ideal conditions. i.e with friction.

The difference in speed then must have been from the friction. So what was the retarding force, given by first determining the difference from ideal acceleration?
 
I still don't get this at all.
 
You aren't given the coefficient of friction, so you can't work it out with F = uN.
Work with the energy lost due to friction, which you do have from part (b).
This is the work done against the force of friction, W = F*d.
 
I... finally came to the answer after about 8 pieces of paper. I think far too into this. Thank you for your help
 
Speed will come with experience! The lesson on this one is that if you can't work forwards, try working backwards.
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
1K
Replies
17
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
13
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
15
Views
3K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 4 ·
Replies
4
Views
3K