How Can You Calculate the Probability of Rolling a Sum of 14 with 7 Dice?

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Homework Statement



Roll 7 dice. What is the probability that the sum of the numbers is 14?


Homework Equations



Possibly a probability generating function because the problem comes from the chapter that deals with it but I can't think of which one (if any actually apply).


The Attempt at a Solution



Here is the solution: 6-7[(13 choose 7)-49]

I really have no idea why. The 67 in the denominator I understand because that is the total number of different ways you can roll 7 dice. Where does the rest come from?
 
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By the definition of probability, the numerator should be the number of different ways you can roll seven dice and get a sum of 14. So how would you count them to get this answer?
 
You might start with a simpler problem to get your head around the harder problem. For example, what's the probability of rolling three dice and getting a total of 6?

The only combinations that produce a total of 6 are (2, 2, 2) and (1, 2, 3). There is only one way to get (2, 2, 2), namely that all three dice have to be 3s, but there are 6 ways to get (1, 2, 3). I've written this as an ordered triple, but I really don't mean it that way--only that one die is a one, another is a two, and the last is a three.

So for this easier problem, what's the probability that three dice will show a total of 6? Can you extend this idea to your problem?



Can you extend this counting strategy to
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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