How can you find displacement given initial position, velocity, and time?

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SUMMARY

The discussion focuses on calculating displacement given initial position, velocity, and time, specifically addressing the formula x = xi + vt + 1/2at². The user initially misapplied this equation due to the presence of changing acceleration, which invalidated their results. After clarification, they realized the importance of using the correct initial velocity (vi) in their calculations. The final correct approach emphasizes the need to account for variable acceleration in displacement calculations.

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Homework Statement


physicscut.jpg

xi=2.0
ti=0

i know the acceleration is -2.0 @ t=3 using the change v/ change t (rise over run)
the vx@ t=3 is two
and t=3
so i need to find the position of x
so i pluged in the formula x= xi+vt+1/2vt2 and I get 11..but I'm way off

Homework Equations



see above

The Attempt at a Solution



tried a few times working from going from the initial x all the way and I get 11 again.

Am I not entering in the sig figs right or am i way off?

I just found this forum and love it!
 
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That equation is for constant acceleration only.
The acceleration changes in this problem, so that equation will not work.

How do you get displacement from velocity in general?
 
Redbelly98 said:
That equation is for constant acceleration only.
The acceleration changes in this problem, so that equation will not work.

How do you get displacement from velocity in general?


i figured it out
I wasn't using the right vi

got me on the right path thanks!
 

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