How can you get power used from step down transformers

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To calculate the power used by a house connected through two step-down transformers, the current in the primary transformer is 48 mA, and the turns ratios are 1:29 and 1:32. The current in the secondary of the first transformer is calculated to be approximately 1.392 A, which then becomes 44.544 A in the secondary of the second transformer. The power delivered to the house is computed using the formula P(avg) = Irms * Vrms, resulting in an average power usage of about 11,000 W. The calculations appear to be correct based on the given transformer specifications and current values.
vaxopy
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Suppose there are two transformers between your house and the high-voltage transmission line that distributes the power. In addition, assume that your house is the only one using electric power. At a substation the primary of a step-down transformer (turns ratio=1:29) receives the voltage from the high-voltage transmission line. Because of your usage, a current of 48 mA exists in the primary of this transformer. The secondary is connected to the primary of another step-down transformer (turns ratio=1:32) somewhere near your house, perhaps up on a telephone pole. The secondary of this transformer delivers a 240-V emf to your house. How much power is your house using? Remember that the current and voltage given in this problem are rms values.

Im lost :confused:
 
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Hint: The voltage steps up as you move back towards the High voltage line, and power in equals power out.
 
I don't know if this is right...
but here's what i did
Is = IpNp/Ns
=48*10^-3 * 29 = 1.392A
Is = IpNp/Ns
=1.392A* 32 = 44.544A
P(avg) = Irms*Vrms = 44.544A * 240V = 1.1*10^4W

is this right?
 

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