How current changes in metals at different temperatures

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Bill Hiker measures a current of 1.000 A through an aluminum wire at 59.0°C in Death Valley and seeks to determine the current at -88.0°C in Antarctica using the same voltage. The relevant equations involve calculating resistance changes due to temperature variations, specifically using Rf = Ri[1 + alpha(Tf - Ti)]. The discussion emphasizes that the voltage remains constant, allowing for simplification in calculations. It is noted that temperatures should be converted to absolute units (Kelvins) for accurate results. The approach involves applying Ohm's law to find the new current after calculating the resistance at the lower temperature.
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Homework Statement



While taking photographs in Death Valley on a day when the temperature is 59.0°C, Bill Hiker finds that a certain voltage applied to a aluminum wire produces a current of 1.000 A. Bill then travels to Antarctica and applies the same voltage to the same wire. What current does he register there if the temperature is -88.0°C? Assume that no change occurs in the wire's shape and size.



Homework Equations



I need to find the new current at a different temperature

The Attempt at a Solution



I used the equation Rf = Ri [1+alpha(Tf-Ti)

And was thinking that i would find Rf and then use ohm's law to find I for the final temperature. but i don't know what V is. or maybe i have to solve using another equation and then subtituing it in.
 
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ketchuppy said:

Homework Statement



While taking photographs in Death Valley on a day when the temperature is 59.0°C, Bill Hiker finds that a certain voltage applied to a aluminum wire produces a current of 1.000 A. Bill then travels to Antarctica and applies the same voltage to the same wire. What current does he register there if the temperature is -88.0°C? Assume that no change occurs in the wire's shape and size.



Homework Equations



I need to find the new current at a different temperature

The Attempt at a Solution



I used the equation Rf = Ri [1+alpha(Tf-Ti)

And was thinking that i would find Rf and then use ohm's law to find I for the final temperature. but i don't know what V is. or maybe i have to solve using another equation and then subtituing it in.
Welcome to PF ketchuppy,

Indeed, you do not know the value of the voltage applied explicitly, but you do know that the voltage applied in both cases was the same.
 
Hootenanny said:
Indeed, you do not know the value of the voltage applied explicitly, but you do know that the voltage applied in both cases was the same.

yes that was stated in the problem . I was thinking that this relates to the resistivity since that changes with temperature. There an equation that relates Resistance to resitivity.

R = Resistivity (L/A).

Not sure if i could go anywhere with that
 
ketchuppy said:
yes that was stated in the problem . I was thinking that this relates to the resistivity since that changes with temperature. There an equation that relates Resistance to resitivity.

R = Resistivity (L/A).

Not sure if i could go anywhere with that
Let's go back to the original problem. Write out the two equations for resistance, one for each location.
 
Hootenanny said:
Let's go back to the original problem. Write out the two equations for resistance, one for each location.

I'm not sure which equation for resistance to use
 
ketchuppy said:
I'm not sure which equation for resistance to use
The one you stated in your opening post:
ketchuppy said:
I used the equation Rf = Ri [1+alpha(Tf-Ti)
But perhaps it would be more useful in this case to use Ohm's law and re-write it as:

\frac{V}{I_f} = \frac{V}{I_i}\left[1+\alpha\left(T_f-T_i\right)\right]
 
Hootenanny said:
But perhaps it would be more useful in this case to use Ohm's law and re-write it as:

\frac{V}{I_f} = \frac{V}{I_i}\left[1+\alpha\left(T_f-T_i\right)\right]

since the voltage is the same, they would drop out of the equation
 
ketchuppy said:
since the voltage is the same, they would drop out of the equation
Indeed they would.
 
would i then proceed to plug in the variables and solve for I(f)
 
  • #10
ketchuppy said:
would i then proceed to plug in the variables and solve for I(f)
Sounds like a plan to me.
 
  • #11
One caveat -- I think the temperatures T need to be in absolute units (Kelvins), not C or F...
 
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