How Do Baud Rate and Frequency Relate in ASK Signal Processing?

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The discussion focuses on calculating the frequency of a signal that repeats 40,000 times in one minute, resulting in a frequency of 666.66 Hz. The baud rate and bit rate in Amplitude Shift Keying (ASK) are also identified as 666.66. It is noted that in ASK, frequency and phase remain constant while only the amplitude changes. Participants seek clarification on how to calculate frequency and phase, emphasizing the relationship between baud rate and frequency. The conversation concludes with the assertion that the frequency aligns with the calculated baud rate.
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What is the frequency in Hertz (cycles per second) of a signal that repeats 40,000 times within one minute? What is the period of the signal? (10 points)


the baud rate is 666.66
the same i the bit rate 666.66 in (ASK) Amplitude shift Keying.

I know that in (ASK) frequency and phase remain constant while only the amplitude change.

But i don't Know how to calculate the frequency and the phase.

can anybody help me?
 
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40,000 cycles per minute * (1 minute / 60 seconds) = x cycles per second.

Note that the units cancel. Solve for x.

- Warren
 
The frequency is the same as the baud rate that you calculated.
 
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