How Do Electron Energy Levels in Mercury Atoms Produce Line Spectra?

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SUMMARY

The discussion focuses on the energy levels of electrons in mercury atoms and their relation to line spectra. Participants calculated the energy change when an electron transitions between levels P and Q, resulting in an energy change of -4.9 eV, equivalent to -7.84 x 10^-19 J. The wavelength associated with this transition was calculated as -2.54 x 10^-7 m. Additionally, the implications of collisions with electrons and photons of 7.0 eV energy were explored, with consensus that the mercury atom would be excited but not ionized.

PREREQUISITES
  • Understanding of atomic energy levels and electron transitions
  • Familiarity with Planck's constant and its application in quantum mechanics
  • Knowledge of photon-electron interactions and excitation processes
  • Basic proficiency in energy calculations involving electron volts (eV) and joules (J)
NEXT STEPS
  • Study the concept of atomic excitation and its effects on electron energy levels
  • Learn about the relationship between energy, frequency, and wavelength using the formula E = hf
  • Explore inelastic and elastic collisions in quantum mechanics
  • Investigate the line spectra produced by different elements and their significance in spectroscopy
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Students and professionals in physics, particularly those studying atomic structure, quantum mechanics, and spectroscopy, will benefit from this discussion.

Spruance
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The diagram shows some of the energy levels of an electron in a mercury atom. Level Q represents the lowest possible energy level.

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(a)Explain why a line spectrum results from an atom with such energy levels.

(b) Calculate the energy change in joules when the electron moves from level P to level Q and determine the wavelength of the spectral line associated with this transition.

(c)Explain what is likely to happen if a moving electron of energy 7.0eV collides with an isolated mercury atom in the ground state.

(d)Explain what is likely to happen if a photon, also of energy 7.0eV were to be incident on the atom.

Planck’s constant = 6.6 x 10-34 Js,
speed of light = 3.0 x 108m/s,
charge on an electron = 1.6 x 10 -19 C

Thanks in advance
 
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I have at least tried to solve b)

-10,4 - (-5,5) = -4,9 eV = -7,84 * 10^-19J


f = E/h = (- 7.84 * 10^-19)/(6.63 * 10^-34) = - 1.18 * 10^15

lamba = (3 * 10^8)/(-1.18 * 10^15) = - 2.54 * 10^-7
 
Have I done something wrong?
 
Spruance said:
I have at least tried to solve b)

-10,4 - (-5,5) = -4,9 eV = -7,84 * 10^-19J


f = E/h = (- 7.84 * 10^-19)/(6.63 * 10^-34) = - 1.18 * 10^15

lamba = (3 * 10^8)/(-1.18 * 10^15) = - 2.54 * 10^-7

Nope, this looks correct to me.

~H
 
Hi

1) is not that important, I can always find some information on internet on it.

However, I didn't find any information in my textbook on c) and d). Anyone able (wanting? ...) to help me out?
 
Last edited:
Think in terms of 'if the electron / photon collides with an electron from a mercury nucleous'. With electron-electron collisions, the collision can either be elastic or inelastic. With a photon, all the energy is always absorbed by the electron. What happens if an electron gains energy?

~H
 
I'm not completely sure
 
Spruance said:
I'm not completely sure

Think about energy levels, excitation...

~H
 
I believe that the mercury atom would be excitated if it collides with a moving electron.
 
  • #10
Spruance said:
I believe that the mercury atom would be excitated if it collides with a moving electron.

You would need to consider the energy of the electron, in relation to the energy levels of the mercury atom.

~H
 
  • #11
I don't think the mercury atom would be ionized
 
  • #12
Spruance said:
I don't think the mercury atom would be ionized

No it wouldn't, what I'm getting at is you should make reference to the energy of the electron / photon in your asnwer and compare it to the energy levels. Excitation is a key word you should use.

~H
 
  • #13
10.4 - 7 = 3.4 eV
 
  • #14
Spruance said:
10.4 - 7 = 3.4 eV

Correct, so it would be excited to the -3.7eV energy level.

~H
 
  • #15
Thanks

What would then happen in d?
 
  • #16
As, I stated previously;

Hootenanny said:
With a photon, all the energy is always absorbed by the electron. What happens if an electron gains energy?

~H
 

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