How do I apply the component method to solve momentum problems in 2 dimensions?

AI Thread Summary
To apply the component method for solving momentum problems in two dimensions, first establish a coordinate system with a convenient x-axis and y-axis. Analyze the problem by breaking down the velocities of colliding objects into their x and y components, ensuring to apply conservation laws separately for each axis. It is crucial to treat these components as scalars for addition and subtraction. After calculating the final components, convert them back into vector form to find the desired quantities like final velocity or angle. Understanding this systematic approach will clarify the analysis of momentum problems involving collisions.
pinkyjoshi65
Messages
260
Reaction score
0
Well, I have been studying Work and Energy for a few days now. I started reading about momentum in 2 dimensions, but i can't seem to understand a thing! I would really appreciate it if someone could help me with this topic.
 
Physics news on Phys.org
well. i have difficulty in understanding the problem questions. For eg: when 2 objects collide they go in different directions with different angles, and the question is to find the velocity. I have difficulty in analysing the problem and drawing the diagram with the vectors.
 
There is a systematic way to deal with that kind of a problem.
First: Define a coordinate system. Choose a convenient x-axis and y-axis, such that you'd have to take the minmum number of components. And the ones that you take, can be easily found out using some trig.
Second: The component method works because, components are scalars, they can be added and subtracted like any other number. So write down the x and y components of the velocities of the bodies before (say a collision) and after. Use the conservation laws for conserving the momentum in the x-axis and the y axis. (Never mix them up!)
Now, when you get the final components that you need, say a final velocity, or angle etc. Just change the components back to the vector form.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top