zoner7, do not be ashamed to post anything online. this site is made to get help/advises from others. Looking at your errors can really help you understand the subject more. So, next time, to be ashamed, just post them.
I also want to give you my up most respect for teaching yourself about physics. It takes real dedication to do so. Congrats! :)
Ok now, let's get to the problem. I am going to break it down in order to make it more understandable.
1) let us say that there was no more friction on the ramp. That means that the total work that the person would need to do to bring the box 2.5m up the ramp would be W=60kg*9.81m/(s^2) * 2.5m=1471.5J. That is using the equation W=Force * distance. The work is being done on only gravity. If you ever did centripetal force, you would know that the centripetal force of anu object orbiting Earth is directed towards the center of earth. It is that force that you are tryin to over come with your box. Because the force due to gravity is acting straight down on the box, you want to overcome it to push it 2.5m up. That is what work against gravity is.
Sure you can calculate the amount of work using the length of the path that the box will be pushed up on (A.K.A the hypothenus) but that is just a waist of time because you have to use a whole bunch of trigonometry for that ****** if you want to see how i would do it using that method, just tell me so in a PRIVATE MESSAGE*******
2)ok, now we are going to put friction back into the problem. The friction is basicaly defined as a resistance to an action. the action is the bo moving up the ramp. The friction is the force that tries to restrain the box from moving up the ramp. A very important equation for friction in a mechanical system is : u=Ff/Fn. u id the coefitional friction, Ff is the frictional force, and Fn is the normal force. To find the amount of friction tha will be applied to the box, you need to reconfigure the equation and make it look like: Ff=u*Fn. You already have u and you can solve for Fn. Because the box is not being pushed straight up, the normal force of the box is not to it's fullest. If the box was being pushed staright up than the normal force would equal the force due to gravity on the box(A.K.A weight). BUt because it is being pushed up at 30 degrees the normal force exposed by the box will be Fn=cos(30degrees)*60kg*9.81m/(s^2)=509.74. **** Fn=cos(angle of ramp)*weight******
Now that you have the normal force, you can find the frictional force that will be acting of the box. Ff=509.74N*0.45=229.28N. The total work agaisnt friction that you will have to do is: W=229.28N*(2.5m/sin(30degrees))=1146.4J *********W=F*d,,,,,,,hypothenus=opposite/sin(angle)*****Now you have the amount of work you will need to bring the box up without friction, the amount of work that will b edone by friction. But WAIT! you still need one more piece of data. If you put a box up a ramp with no friction, the box is going to slide down the ramp. So we can say that friction helps maintain the box at it's position when not moving. But the friction does not always have to keep a box at a spot. the "sliding" force can over come friction and make th ebox go down the ramp. So now, we are goin to find what the sliding force is.
3)*****Fs=sin(angle of ramp)*weight***** Fs= sin(30 degrees)*(60kg*9.81m/(s^2))=294.3N. This sliding force, if the force due to gravity at an angle of 30 degrees for that particular object. Now look, that force is greater than the frictional force. That only means that if the object was placed on the ramp and no one pushing, the box would slide down. So now, we need to find by how much the force of friction will decrease the "sliding" force. We do :294.3N-229.28N = 65.02N. that resulting force is going to push the box down the ramp. So now we need to know how much work it wil take to take care of that that "sliding" force up to when it reaches the top of the ramp. So we do: W=65.02N*5m= 325.1J
So now, we have all the work will will need to bring the box to the top. All we have to do now is to add them up. So...: total work=1471.5J + 1146.4J + 325.1J=2943J
2943Joules is the answer considering that there is no acceleration.
sry that it is that long :)
hope you had fun reading it haha :)
private message me if you have any questions
) also (different method). 
