How do I change the variable in this expression?

AI Thread Summary
The discussion revolves around performing a change of variable in a mathematical expression to rewrite it as a single product. Participants emphasize the importance of introducing a new variable to align the limits of the two product expressions, specifically suggesting letting j = k + 1. This adjustment allows for consistent indexing from 1 to n, facilitating the transformation of the expression. Confusion arises regarding the correct approach to variable substitution, with clarification provided that the focus should be on changing the index rather than the expression itself. Ultimately, the goal is to simplify the expression through proper variable manipulation.
PolyFX
Messages
30
Reaction score
0

Homework Statement


Rewrite the following expression as a single product.
Hint: Perform a change of variable first.

29bh5wy.gif

Homework Equations


The Attempt at a Solution


I looked at the example from the book regarding a change of variable. They first started out by calculating the upper and lower limits of the expression. However, in this the upper limits and lower limits are different. For example, the right product expression has an upper limit of n - 1 while the left has an upper limit of n. Furthermore, I can make for example j = k+1 but then what about k+2? Would I need to introduce a new variable or do i make j = (k+1) + 1 to represent k +2?

How do I go about performing a change of variable with this expression?
 
Physics news on Phys.org
PolyFX said:
… Would I need to introduce a new variable or do i make j = (k+1) + 1 to represent k +2?

How do I go about performing a change of variable with this expression?

HI PolyFX! :smile:

You'll avoid mistakes if you do introduce a new variable, to go from 0 to n-1.

You can then turn that new variable back to k (it's only a "dummy" variable :wink:) in the next step.
 
Hi sorry for the late reply,

I am still somewhat confused about how to approach this question. So far this is how I've startend it.

Let j = K+1/K+2

Therefore when k = 0,
j = 1/2
and when K = n - 1,
j = (n-1) + 1 / (n-1 ) + 2
j = n


So I introduce another variable for the other product expression?

so let x = K+1/K+2
when k = 1
j=2/3
and when k = n
j = n+1/n+2

I am stuck here.


To me I get the feeling that I am definitely doing something wrong. Would be great if someone get further help me out here.


-Thank you
 
PolyFX said:
Hi sorry for the late reply,

I am still somewhat confused about how to approach this question. So far this is how I've startend it.

Let j = K+1/K+2
No! You've completely misunderstood. The point was to change the "variable" (index), not the expression itself!

The first product goes from k=0 to n-1. If we let j= k+1, it will go from j= 0+1= 0 to (n-1)+ 1= n, just like the second product.
Now, change the expression to j: since j= k+1, k= j- 1 and so k+ 1 becomes j while k+2 becomes j-1+ 2= j+1. Now you have
\left[\Pi_{j=1}^n\frac{j}{j+1}\right]\left[\Pi_{k=1}^n\frac{k+1}{k+2}\right]

Now, since the "k"s are dummy indexes, you can just let the "j" in the first product be "k" to get
\left[\Pi_{k=1}^n\frac{k}{k+1}\right]\left[\Pi_{k=1}^n\frac{k+1}{k+2}\right]
and now you can multiply those.

Therefore when k = 0,
j = 1/2
and when K = n - 1,
j = (n-1) + 1 / (n-1 ) + 2
j = n


So I introduce another variable for the other product expression?

so let x = K+1/K+2
when k = 1
j=2/3
and when k = n
j = n+1/n+2

I am stuck here.


To me I get the feeling that I am definitely doing something wrong. Would be great if someone get further help me out here.


-Thank you
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
Back
Top