How do i compute for the volume if the density of ore is not given?

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To compute the volume of an ore sample when its density is unknown, the buoyant force can be used, calculated as the difference between the weight in air and the apparent weight in water. In this case, the buoyant force is 6.3 N, derived from the weights of 17.50 N and 11.20 N. Using the formula for buoyancy, the volume of water displaced, which equals the volume of the ore, can be determined by dividing the buoyant force by the product of water's density (1000 kg/m^3) and gravitational acceleration (9.8 m/s^2). This results in a volume of approximately 6.43 x 10^-4 m^3. Thus, the volume of the ore can be accurately calculated without knowing its density.
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Homework Statement



An ore sample weights 17.50 N in air. When th sample is suspended by a light cord and totally immersed in water, the tension in the cord is 11.20 N. What is the total volume of the object?

Homework Equations


B = rho * volume displaced* g

B= weight in air - weight apparent

The Attempt at a Solution


I took the tension in the string as equal to the apparent weight. So using that I computed for the buoyancy: 17.50N - 11.20N = 6.3N

So, 6.3N = rho*volume of water displaced *g

how do i compute for the volume if the density of ore is not given?
 
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Volume of water displaced = volume of ore

You know the density of water so how about calculating the volume of water displaced?

Jared
 


So, is it just 6.3N/(9.8*1000kg/m^3) = 6.43x10^-4 m^3
 


Fbuoyant = density * volume * gravity

Rearranging gives Fbuoyant / (density * gravity) = volume

6.3 / (9.8 * 1000) = 6.43x10^-4 m^3

Jared
 

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