How Do I Evaluate a Summation Involving Binomial Coefficients?

Click For Summary
SUMMARY

The evaluation of the summation \(\sum_{k=0}^d \binom{n+d-k}{n}\) can be effectively simplified by changing the variable of integration to \(k' = d - k\). The resulting expression is \(\binom{n+d+1}{d}\), which can also be represented as \(\binom{n+d+1}{n+1}\). For detailed steps and methodologies, refer to the provided resource.

PREREQUISITES
  • Understanding of binomial coefficients and their properties
  • Familiarity with summation notation and variable substitution
  • Basic knowledge of combinatorial mathematics
  • Ability to interpret mathematical expressions and transformations
NEXT STEPS
  • Study the properties of binomial coefficients in depth
  • Learn about variable substitution techniques in summations
  • Explore combinatorial identities and their applications
  • Review advanced topics in combinatorial mathematics
USEFUL FOR

Mathematicians, students studying combinatorics, educators teaching binomial coefficients, and anyone interested in advanced summation techniques.

mathstime
Messages
25
Reaction score
0
how do I evaluate [tex]\sum_{k=0}^d \binom{n+d-k}{n}[/tex] ?
 
Physics news on Phys.org


I don't know the method. But first you could change the variable of integration to [itex]k'=d-k[/itex] and then you look it up :)
I think the answer is
[tex]\binom{n+d+1}{d}[/tex]
 


The answer is:
[tex]\left(<br /> \begin{array}{c}<br /> n+d+1 \\<br /> n+1<br /> \end{array}<br /> \right)[/tex]

Please refer to:

http://www.voofie.com/content/76/evaluating-summation-involving-binomial-coefficients/"

for the steps and how to deal with problem of this type.
 
Last edited by a moderator:

Similar threads

  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 11 ·
Replies
11
Views
4K
Replies
3
Views
2K