How do I find the current in this circuit?

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SUMMARY

The discussion focuses on calculating currents in a circuit using Kirchhoff's Current Law (KCL) and Kirchhoff's Voltage Law (KVL). The calculated currents are I1 = 0.1429 A, I2 = 0.4286 A, and I3 = 0.2857 A. The user demonstrates the application of KVL in two loops and suggests using nodal analysis to find the voltage at node A. The provided Wolfram Alpha links facilitate solving the equations for I1 and I2.

PREREQUISITES
  • Understanding of Kirchhoff's Current Law (KCL)
  • Familiarity with Kirchhoff's Voltage Law (KVL)
  • Basic knowledge of circuit analysis techniques
  • Experience with using Wolfram Alpha for solving equations
NEXT STEPS
  • Study advanced applications of Kirchhoff's Laws in complex circuits
  • Learn about nodal analysis in electrical engineering
  • Explore the use of simulation tools like LTspice for circuit analysis
  • Investigate the impact of resistor values on current distribution in circuits
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing electrical circuits using KCL and KVL.

clurt
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< Moderator Note -- thread moved from the EE forum to the Homework Help forums >[/color]

Please view the attached.

The answers are:
i1 0.1429
i2 0.4286
i3 0.2857

So how do I work this out? I assume you use kirchhoffs current law, can someone show me the step? Thanks :)
 

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For loop I we can write this KVL
10V - I1*R1 - (I1 + I2)*R3 = 0
And for loop II
20V - I2*R2 - (I2 + I1)*R3 = 0

Solve this for I1 and I2. And from KCL I3 = I1 + I1

http://www.wolframalpha.com/input/?i=10 - I_1*10 - (I_1 + I_2)*40 = 0 , 20 - I_2*20 - (I_2 + I_1)*40 = 0 solve I_1 and I_2

Or we can use nodal analysis.
For node A we can write a KCL
I1 + I2 = I3

I1 = (10V - VA)/R1
I2 = (20V - VA)/R2
I3 = VA/R3

And solve for VA voltage.
http://www.wolframalpha.com/input/?i=(10 - a)/10 + (20 - a)/20 = a/40
 
Last edited:
Jony130 said:
For loop I we can write this KVL
10V - I1*R1 - (I1 + I2)*R3 = 0
And for loop II
20V - I2*R2 - (I2 + I1)*R3 = 0

Solve this for I1 and I2. And from KCL I3 = I1 + I1

http://www.wolframalpha.com/input/?i=10 - I_1*10 - (I_1 + I_2)*40 = 0 , 20 - I_2*20 - (I_2 + I_1)*40 = 0 solve I_1 and I_2

Or we can use nodal analysis.
For node A we can write a KCL
I1 + I2 = I3

I1 = (10V - VA)/R1
I2 = (20V - VA)/R2
I3 = VA/R3

And solve for VA voltage.
http://www.wolframalpha.com/input/?i=(10 - a)/10 + (20 - a)/20 = a/40
thanks mate
 

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