Dependent source problem using KVL

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SUMMARY

The discussion centers on resolving issues with dependent current sources in circuit analysis using KVL (Kirchhoff's Voltage Law). The user reported currents I1=3.125 A, I2=-1.857 A, and I3=4.375 A, along with a power output of -46.875 W from the dependent current source. The solution involves applying the super mesh technique to correctly account for the shared current source between mesh1 and mesh2, which was overlooked in the user's initial equations.

PREREQUISITES
  • Understanding of Kirchhoff's Voltage Law (KVL)
  • Familiarity with dependent current sources
  • Knowledge of mesh analysis in circuit theory
  • Proficiency in the super mesh technique
NEXT STEPS
  • Study the super mesh technique in detail
  • Practice solving circuits with dependent sources using KVL
  • Review examples of mesh analysis in circuit simulations
  • Explore the impact of dependent sources on circuit power calculations
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing circuits with dependent sources will benefit from this discussion.

Michael_0039
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Homework Statement
Using KVL find the current through the resistors and Power of the dependent current source.
Relevant Equations
nil
Hi all,

I was trying to solve this but I'm stuck as you can see in my notes below:

New Doc 2019-10-13 16.55.53_1.jpg

New Doc 2019-10-13 16.55.53_2.jpg


Using simulator the I1=3.125 A | I2=-1,857 A | I3=4,375 A and Power of the dependent current source = -46.875 W

1570976039548.png


Any idea, what could be wrong ?Thanks.
 
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In your loop 2 equation you're ignoring the voltage across the current source? So are you pretending it's zero volts?
 
Michael_0039 said:
Using simulator the I1=3.125 A | I2=-1,857 A | I3=4,375 A and Power of the dependent current source = -46.875 W

View attachment 251072


Any idea, what could be wrong ?Thanks.

Since mesh1 and mesh2 share a current source, you must use the super mesh technique, combining mesh1 and mesh2 for your second equation. Have you learned the super mesh technique?
 
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