How Do I Integrate (x^2 + 7x + 10) / (x + 2)?

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To integrate (x^2 + 7x + 10) / (x + 2), the expression can be factored to (x + 5)(x + 2) / (x + 2), allowing the (x + 2) terms to cancel. However, it's important to note that there is a singularity at x = -2, which excludes this point from the integration domain. The integral can still be evaluated by breaking it into two parts around the singularity. The discussion highlights that while the integral exists despite the discontinuity, the function must be treated carefully in regions containing the singularity. Understanding these nuances is crucial for correctly performing the integration.
Guero
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how can i integrate:
x^2+7x+10 dx
x+2

i assume it's by substitution, but i can't work it out.

sorry for the formatting, btw
 
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Factor the top, it cancels.
 
Guero said:
how can i integrate:
x^2+7x+10 dx
x+2

i assume it's by substitution, but i can't work it out.

sorry for the formatting, btw

(x+5)(X+2) =x+5
(x+2)
I don't know nothing about integrate. But I think you have to factor the trinomial then divide.
 
Note the singularity at x = -2, it can't be integrated in a region containing this point.
 
Not really.It can't be defined at x=-2,which means that automatically that point is excluded from the integration domain.

Daniel.
 
thanks. should've seen it.
 
Does the integral

\int_{-3}^1 \frac{x^2+7x+10}{x+2} \ dx exist, dex? As its written?
 
I don't know.U'll have to break it into 2 and evaluate each limit.(I wasn't talking about a definite integral,so your (counter)example is useless).

Daniel.
 
whozum said:
Note the singularity at x = -2, it can't be integrated in a region containing this point.

dextercioby said:
Not really.It can't be defined at x=-2,which means that automatically that point is excluded from the integration domain.

Its the same thing.
 
  • #10
However, the integral is a "smoothing" operation. The integral of a function with removable discontinuity exists and is exactly the same as the integral of the function with the discontinuity removed.
 
  • #11
whozum do you agree that x^2 is integratable, what about \frac{(x^2)(x+1)}{x+1}?
 
  • #12
Theyre both integrable, just the latter isn't continuous.
 
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