How do I simplify 2^(-m) x 3^(-m) x 6^(2m) x 3^(2m) x 2^(2m) as a power of 6?

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To simplify the expression 2^(-m) x 3^(-m) x 6^(2m) x 3^(2m) x 2^(2m) as a power of 6, recognize that 6 can be expressed as the product of its prime factors, 2 and 3. By rewriting the terms with base 2 and base 3 in terms of base 6, the expression can be transformed. The key steps involve combining like bases and applying the properties of exponents. Ultimately, the simplification leads to the result of 6^(3m). Understanding the relationship between the bases is crucial for solving similar problems.
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Homework Statement
Write 2^(-m) x 3^(-m) x 6^(2m) x 3^(2m) x 2^(2m) as a power of 6.
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Write 2^(-m) x 3^(-m) x 6^(2m) x 3^(2m) x 2^(2m) as a power of 6.
Hi everyone

Could someone please help me with a yr 10 maths problem? It's for my niece. I've done 2nd yr uni maths and can't seem to solve it.

Write 2^(-m) x 3^(-m) x 6^(2m) x 3^(2m) x 2^(2m) as a power of 6.

I've attached my attempt in the file. I get stuck at the point where I need to get rid of the base 2 and base 3 terms.

The answer is 6^(3m), but I don't know how to get there. Thanks
 

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Darkmisc said:
I've done 2nd yr uni maths
Then you should know hat ##2\times 3=6## !
 
Thanks. It's been a while since I've done maths.
 
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