How Do I Solve -0.874 = sin2θ in Physics?

  • Thread starter Thread starter twenty5
  • Start date Start date
twenty5
Messages
93
Reaction score
0
BLAHH! I can't figure this one out!

how do I isolate θ??

Statement is...

-0.874 = sin2θ


jeeebuss can someone walk me through LOL! I need it to finish off a 4 hour physics question =/
 
Physics news on Phys.org
Hi twenty5! :smile:

walk this way … if x = sinθ, then θ = sin-1x (or arcsin x) :wink:
 
tiny-tim said:
Hi twenty5! :smile:

walk this way … if x = sinθ, then θ = sin-1x (or arcsin x) :wink:

so, if -0.874 = sin2θ

then...
sin-1(-0.874) = 2θ

then...

(sin-1(-0.874))/2 = θ?
 
twenty5 said:
so, if -0.874 = sin2θ

then...
sin-1(-0.874) = 2θ

then...

(sin-1(-0.874))/2 = θ?

Yes, except …

i] it's normal to have only positive numbers inside the sin-1

ii] you didn't say what the range of θ was … did they specify 0 < θ < π or 2π or what? … there may be several solutions, especially since you're divding the angle by 2 :wink:
 
tiny-tim said:
Yes, except …

i] it's normal to have only positive numbers inside the sin-1

ii] you didn't say what the range of θ was … did they specify 0 < θ < π or 2π or what? … there may be several solutions, especially since you're divding the angle by 2 :wink:

hmm not sure because I'm using this to do this... https://www.physicsforums.com/showthread.php?t=293717

the very final post should be mine =P

right, since the football player is kicking the ball above ground on a horizontal plane (straight field), and he is kicking it forward to a distance other than where he is standing, it has to be somewhere between 0o and 89o

so, the answer I ended up with was -30.46o... so would that mean it is... wrong? LOL! omg... can't believe I spent 4 -5 hours to end up with a wrong answer -__- so depressing..
 
hmm … your minus sign seems to have come in post #18, but you don't show how you got it …

yes, you need an answer between 0 and 90º, but your formula should give you two such answers.

and I'm going to bed now … :zzz:​
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top