How Do I Solve for L in an Inductance Equation?

  • Thread starter Thread starter Loopas
  • Start date Start date
AI Thread Summary
To solve for L in the inductance equation 2*pi*f = √(1/(LC) - R²/(4L²)), start by squaring both sides to eliminate the square root. After squaring, rearrange the equation to collect all terms on one side, setting the equation to zero. Next, combine the terms over a common denominator to facilitate solving for L. This approach allows for isolating L and finding its value. Proper manipulation of the equation is crucial for determining the inductance accurately.
Loopas
Messages
55
Reaction score
0
Hi everyone,

For my physics lab I have to solve for inductance, given the following equation and values for C, R, and f:

2*pi*f = \sqrt{\frac{1}{LC}-\frac{R^{2}}{4L^{2}}}

I'm just not really sure how to solve for L. I started by squaring both sides but it just seems like I can't solve for inductance because there's two terms for L.

Thanks
 
Physics news on Phys.org
After squaring collect everything on the left hand side (leaving zero on the right). Put over a common denominator...
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top