How do I solve for x in this equation?

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To solve the equation -x^3 + 6x^2 - 11.998x + 8 = 0, various methods can be employed, including factoring and numerical methods like Newton's method. The equation is cubic, and while it may not have rational roots, the rational root theorem suggests testing integers such as ±1, ±2, ±4, and ±8. The approximate solution x = 2.16 indicates that exact roots may not be rational due to the non-integer coefficient. Ultimately, using a calculator or numerical methods is recommended for finding solutions to cubic equations.
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Homework Statement


How can I calculate x in this equation: -x^3+6x^2-11.998x+8 = 0?


Homework Equations



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The Attempt at a Solution



**I tried factoring, but how??
**I know that the answer turns out to be x=2.16, but how did this come about?
 
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What course is this from? 2.6 is not an exact answer so maybe they want you to use Newton's method? There are a few ways of solving this-- but the method will depend on what course you are taking.
 
Hi Cuisine123! :smile:

(try using the X2 tag just above the Reply box :wink:)
Cuisine123 said:
How can I calculate x in this equation: -x^3+6x^2-11.998x+8 = 0?

It's a cubic, and you wouldn't be expected to know how to solve it in an exam.

(Basically, you put x = y + a so that the equation is of the form y3 + Ay + B = 0, and then use a formula)

Just use a calculator! :wink:
 
By the "rational root theorem" the only possible roots are \pm 1, \pm 2, \pm 4, and \pm 8. If that "11.998" were "12", then 2 would be triple root. As it is, however, that equation has no rational roots.
 
There is an analogous formula for polynomials of degree three: The solution of ax3+bx2+cx+d=0 is

cubic.gif
 
danielatha4 said:
The solution of ax3+bx2+cx+d=0 is …

shouldn't there be three solutions? :confused:
 
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