How Do I Solve Polynomial Division and Trigonometric Identities?

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To solve the polynomial division of (x^2 - 8x + 15) by (3 - x), it is suggested to reorder the polynomials in descending powers and consider synthetic division. The correct approach involves recognizing that dividing by (3 - x) is equivalent to dividing by (-1)(x - 3). For the trigonometric identity problem, the expression √(a^2 - a^2 sin^2 θ) simplifies to √(a^2(1 - sin^2 θ)), which can be factored out as a cos θ. Understanding these steps clarifies the division and identity processes.
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Homework Statement


I forgot how to divide this

1.) x^2 + 15 -8x divided by 3 - x

I don't know how to start since 3 has nothing to do with x^2.
The result from the book is 5 - x.


I also don't understand this problem which uses trigonometric identities.
if x = a sin theta then

2.) square rt of a^2 - x^2

= square rt of a^2 - a^2 sin^2 theta
= square rt of a^2 square rt of 1 - sin^2 theta
= a cos theta .

I don't understand why does

square rt of a^2 - a^2 sin^2 theta

= square rt of a^2 square rt of 1 - sin^2 theta ?



Homework Equations





The Attempt at a Solution



Thanks in advance.
 
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1) When dividing, rewrite all the polynomials with highest power of x first, then decreasing powers of x from there.

2) Firstly, we can factor a^2-a^2 sin^2 theta as a^2( 1 - sin^2 theta).

Then we can break up the squareroot using \sqrt{xy} = \sqrt{x} \sqrt{y}.
 
Thanks by ordering the polynomials and using syntethic division I have 3 dividing 1 -8 +15 which equals x - 5 ?
 
Jimmy84 said:
Thanks by ordering the polynomials and using syntethic division I have 3 dividing 1 -8 +15 which equals x - 5 ?
No. Dividing x2 - 8x + 15 by 3 - x is equivalent to dividing -x2 + 8x - 15 by x - 3.
 
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