How Do I Solve This Complex Square Root Equation?

AI Thread Summary
To solve the complex square root equation n_{0}=1.5*10^{15}+\sqrt{(1.5*10^{15})^{2}+[(0.05)n_{0}]^{2}}, isolate the square root on one side and then square both sides. This leads to the equation [n0-(1.5*10^{15})]²=(1.5*10^{15})²+0.0025n0². After simplifying and rearranging, the solution for n0 can be found. The final answer is n0=3.0075*10^{15}. Properly applying these algebraic steps will yield the correct result.
snoothie
Messages
17
Reaction score
0

Homework Statement



Can someone advice me how to solve this square root equation?
n_{0}=1.5*10^{15}+\sqrt{(1.5*10^{15})^{2}+[(0.05)n_{0}]^{2}}

The answer should be n0=3.0075*1015

I can't figure out how to open up the square root to solve the equation for n0.
Stuck here staring at the equation...
 
Physics news on Phys.org
snoothie said:

Homework Statement



Can someone advice me how to solve this square root equation?
n_{0}=1.5*10^{15}+\sqrt{(1.5*10^{15})^{2}+[(0.05)n_{0}]^{2}}

The answer should be n0=3.0075*1015

I can't figure out how to open up the square root to solve the equation for n0.
Stuck here staring at the equation...

Isolate the square root on one side of the equals sign, then square both sides.
 


solved. but must take note to make the equation:

[n0-(1.5*1015)]2=(1.5*1015)2+0.0025n02

Thanks and cheers
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top