How Do Isotope Tracers Determine Mixing Ratios in Water Samples?

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    Isotope Mixing
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Isotope tracers can determine mixing ratios in water samples by applying the isotopic mixing equation, which relates the isotopic composition of the mixture to the contributions from each sample. In the given problem, Sample 1 has a δ18O value of -1 per mil, and Sample 2 has a δ18O value of -20 per mil, with the mixture at -15 per mil. By isolating the fraction of water from each sample using the equations provided, it is determined that 26% of the mixture comes from Sample 1 and 74% from Sample 2. This demonstrates how isotopic analysis can effectively quantify the proportions of different sources in a mixed water sample. Understanding these mixing ratios is crucial for various environmental and hydrological studies.
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Homework Statement


Two water samples are mixed. Sample 1 has δ18O-H2O = -1(per mil), Sample 2 has δ18O-H2O = -20 (per mil), and the mixture has δ18O-H2O = -15 (per mil).

What fraction of water came from sample 1 and what fraction came from sample 2?
Assume that F = the fraction of the water that came from Sample 1
Assume that 1-F = the fraction of the water that came from Sample 2

Homework Equations


QT=Q1+Q2 where QT is total percent, and Q1 and Q2 are the percent contributions to the mixture from samples 1 and 2, respectively.

δ18OTQT = δ18O1Q118O2Q2

The Attempt at a Solution


I've uploaded my work...if I am using the write mixing equation for two endmembers, my problem really is then just isolating and solving for F. From there I can solve for F2
 

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@Greg Bernhardt I've used the Isotopic Mixing Equation: δ18OTQT = δ18O1Q118O2Q2 in order to solve it. It can also be solved using a Two-component Mixing Model, according to the equations: F2 = (δ18Omix18O1) / (δ18O218O1) ; F1 = 1 - F2
Using both equations, you find that the fraction of the sample coming from sample 1 is 0.26 (or 26%), and percent contribution from sample 2 is 0.74 (or 74%)
 
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