I How Do Supremum and Infimum Relate When s < t for All s in S and t in T?

AI Thread Summary
In the discussion, participants explore the relationship between the supremum of set S and the infimum of set T under the condition that every element s in S is less than every element t in T. The key argument is that if sup(S) were greater than inf(T), it would contradict the definition of supremum and infimum, leading to a logical inconsistency. By assuming inf(T) < sup(S), it is demonstrated that there must exist an element in S that is less than inf(T), which in turn implies the existence of an element in T that is less than this element in S. This contradiction confirms that sup(S) must indeed be less than or equal to inf(T). The conclusion is that sup S ≤ inf T holds true under the given conditions.
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Let S and T be subsets of R such that s < t for each s ∈ S and each t ∈ T. Prove carefully that sup S ≤ inf T.

Attempt:

I start by using the definition for supremum and infinum, and let sup(S)= a and inf(T)= b

i know that a> s and b< t for all s and t. How do i continue? , do i prove it directly starting from s< t or will it be easier to use proof by contradiction?
 
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wang jia le said:
Let S and T be subsets of R such that s < t for each s ∈ S and each t ∈ T. Prove carefully that sup S ≤ inf T.

Attempt:

I start by using the definition for supremum and infinum, and let sup(S)= a and inf(T)= b

i know that a> s and b< t for all s and t. How do i continue? , do i prove it directly starting from s< t or will it be easier to use proof by contradiction?

Try contradiction.
 
Usually the definition of upper/lower bound would only imply s \leq \sup(S) for all s \in S and \inf(T) \leq t for all t \in T. In other words, the upper and lower bounds can be in the set themselves. The stated result should hold regardless though.

Just start with \inf(T) \lt \sup(S) and go from there. There must be an s \in S such that \inf(T) \lt s ( otherwise \inf(T) would be an upper bound of S that's less than \sup(S) ). But then, for similar reasons, there must be a t \in T such that t \lt s ( fill in the details ).
 
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