How Do You Calculate Cell Potentials for Electrochemical Couples?

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To calculate the cell potential for the Zn^2+/Zn and Ag^1+/Ag couple, the standard reduction potentials are used: Zn^2+/Zn at -0.76 V and Ag^1+/Ag at +0.80 V. The correct approach does not require balancing the half-reactions or flipping the zinc reaction; instead, both half-reactions can be considered at their respective potentials. Adding the potentials directly gives a total cell potential of 1.56 V. Despite the initial confusion, this calculation appears correct, and the homework feedback may need reevaluation.
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Homework Statement



Calculate the potential of a Zn^2+/Zn and Ag^1+/Ag couple.

Homework Equations



Zn^2+ + 2e^1– ⇌ Zn E= –0.76 V
Ag^1+ + e^1– ⇌ Ag E= +0.80 V

The Attempt at a Solution



First I know to multiply the silver half reaction by two so that each half reaction has two electrons. Then I flip the zinc reaction and switch the sign of its energy. Then, I added the two energies to get a cell potential of 1.56V. However, my homework is telling me that this is incorrect. I can not think of any reason why that is so. Any suggestions? Any help would be much appreciated.
 
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E is not energy. You don't need to balance reaction to calculate potential. You don't flip the reaction - direction doesn't matter, both oxidation and reduction are both taking place at exactly the same potential.

All that being said, 1.56 looks fine to me... I can be missing something - it happens, especiall early in the morning - but I think it is OK.

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