How Do You Calculate Final Speed and Net Force in Physics?

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To calculate the final speed of a car that requires 5.8 kJ of work to move from rest over a distance of 29.8 m, the equation used is 5800 J = 1/2 mv^2, yielding a final speed of approximately 2.27 m/s. For determining the net horizontal force exerted on the car, the equation W = Fd cos(θ) is relevant, but clarification is needed on the meaning of "net" force in this context. The net force refers to the vector sum of all forces acting on the car. Understanding these concepts is crucial for solving the physics problem accurately.
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Homework Statement


Part 1. A 2.25 × 10^3 kg car requires 5.8 kJ of work to move from rest to some final speed. During this time, the car moves 29.8 m.
Neglecting friction, find a) the final speed. Answer in units of m/s

Part 2.
b.)the net horizontal force exerted on the car. Answer in units of N

Homework Equations


For Part 1. I did 5800j=1/2mv^2 plugged in and got 2.2705848, which is correct
For Part 2 I guess it would be W=fdcos?

The Attempt at a Solution


For Part 1. I did 5800j=1/2mv^2 plugged in and got 2.2705848, which is correct
For part 2 I did 5800=fdcos but i am confused on what they mean by saying net.
 
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net force just means the vector sum of forces when different forces are applied to an object
 

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