How do you calculate inductance in an RL circuit?

AI Thread Summary
To calculate the inductance in an RL circuit with a resistance of 0.300 ohms and a current increasing to one fourth of its final value in 1.40 seconds, the user initially struggled with the equations V=IR and I= V/R(1-e^(Rt/L)). It was clarified that the voltage (V) can be treated as a variable, allowing for the use of ratios in the time constant equation. The user attempted to relate the time constant to inductance using the formula 1/t = L/R but found it unhelpful. Ultimately, the user resolved their confusion about the inductance calculation.
GreenLantern674
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[SOLVED] Inductance RL Circuit

Calculate the inductance in an RL circuit in which R = 0.300 and the current increases to one fourth its final value in 1.40 s.

I tried doing this with V=IR, (I know, the easy way didn't work).
I also tried I= V/R(1-e^(Rt/L)) but I don't know what V would be in this equation. Can someone help me out here?
 
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GreenLantern674 said:
Calculate the inductance in an RL circuit in which R = 0.300 and the current increases to one fourth its final value in 1.40 s.

I tried doing this with V=IR, (I know, the easy way didn't work).
I also tried I= V/R(1-e^(Rt/L)) but I don't know what V would be in this equation. Can someone help me out here?

The value of V itself will not matter -- you are dealing with ratios and the time constant equation that you show. Just leave it as a variable "V", and see if you can solve for the inductance...
 
Okay, so what you said got me thinking, and I remembered that the time constant equals 1/t and that equals L/R so I set 1/1.4 = L/0.3 but that didn't work. Am I on the right track?
P.S. is inductance negative?
 
Never mind. I got it.
 
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