How Do You Calculate Initial Velocity of an Arrow Shot Straight Up?

AI Thread Summary
To calculate the initial velocity of an arrow shot straight up, the relevant formula is v^2 = initial velocity^2 + 2(-9.8 m/s²)(displacement). In this case, the arrow reaches a height of 25.0 meters after 2 seconds. The initial velocity is not zero, as it must account for the upward motion before reaching maximum height. The calculated initial velocity is approximately 22.3 m/s. Clarification on the question's specifics is essential for accurate calculations.
swatmedic05
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You shoot an arrow into the air. Two seconds later (2.00 ) the arrow has gone straight upward to a height of 25.0 above its launch point
What is the initial velocity or the formula I would use to find
 
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Are you looking for max velocity? Initial velocity at what point? Before you shot it would be zero. At max height it would also be zero.
 
the right answer is 22.3 but i don't know how the book got that answer
 
can you post the entire question.
 
That is the entire question: My homework is on masteringphysics.com
 
There is not enough information to find the answer.
 
I apologize I think I just figured it out. Here is the formula
velocity & displacement:
v^2=initial velocity+2(-9.8m/s^2)(25m) but your initial velocity should be zero so are you sure that that is what the question is asking for.
 

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