How Do You Calculate Molar Masses from Diffusion Rates and Density?

AI Thread Summary
To calculate the molar masses of two gases in a mixture with known density and diffusion rates, the relationship between diffusion rates and molar mass can be utilized. The diffusion rate ratio indicates that the molar mass of gas B is 1.5625 times that of gas A. The ideal gas law can be applied to determine the molar masses by using the density of the gas mixture. Understanding the properties of ideal gases is crucial for solving such problems. The discussion highlights the importance of foundational chemistry knowledge for tackling university-level questions.
Canuck156
Messages
32
Reaction score
0
Hi, this is the question I'm having trouble with:

A gas mixture is known to contain equal numbers of moles of two gases. The mixture has a density of 1.47g/L at 1.00 atm and 298K. In a diffusion experiment, one of the gases was found to diffuse 1.25 times faster than the other under the same conditions. What are the respective molar mases of the two gases?

I've found that 1.25=\sqrt{\frac{M_B}{M_A}} Therefore 1.5625=\frac{M_B}{M_A}, where M_B is the molar mass of gas B. However, from there I have no idea where to go next. I think I'm supposed to use the ideal gas law, but I'm not sure how to apply it when there's a mixture of gases. Any help is appreciated! Thanks!
 
Physics news on Phys.org
Nobody knows how to do this? Come on, surely someone must be able to help? :smile:
 
does the ideal gas law depend on
what those 10^23 objects are?
(an ideal gas = atoms don't interact)

so find (n_moles/V)(m/mole).
 
Oh... OK, I get it now. Thanks lightgrav. I didn't realize that that was one of the properties of an ideal gas... Maybe I shouldn't be doing University Chem without having done High School Chem first... :rolleyes:
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top