Chemistry How Do You Calculate Moles and Concentration of Ca(2+) in CaC2O4H2O?

AI Thread Summary
To calculate the moles of Ca(2+) in CaC2O4H2O, first confirm the moles of CaC2O4H2O, which is 1.6 x 10^-3. Since each mole of CaC2O4H2O contains one mole of Ca(2+), the moles of Ca(2+) will also be 1.6 x 10^-3. To find the concentration of Ca(2+), divide the moles of Ca(2+) by the volume of the solution in liters. The mass percentage of Ca(2+) is not directly needed for these calculations, as the stoichiometry of the compound provides the necessary information. Understanding the relationship between moles of the compound and its components is crucial for accurate calculations.
Dooga Blackrazor
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Homework Statement



I did an experiment and found the weight of CaC(2)O(4)H(2)0 to be 31.4966 subtracted by the weight of a crucible which is 31.2612.

I put this for my weight of CaC204H20 (as I can't think of any other weight that it would be requested). I followed the next question calculating molecular weight. 146.112. After that I calculated the moles of CaC204H20 to be 1.6 x 10^-3 (not sure on this).

I now need the moles of Ca(2+ charge). There are 27.42% Ca(2+) mass percentage of it.

I don't know what to do from there. Same goes for the concentration of Ca(2+)


Homework Equations





The Attempt at a Solution



If I had to guess, I would say the moles of Ca2+ are 0.2742 times 146.112, but I am not sure.

Concentration, I have no clue. I have been looking through my online notes on this for hours now. Thanks for any help.
 
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Your calculation of the moles of CaC2O4*H2O is correct. According to the formula of the compound, how many moles of Ca2+ does one mole of the compound contain?
 
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