Chemistry How Do You Calculate Moles from Grams for BaCl2 *2H2O?

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To calculate moles from grams for BaCl2 * 2H2O, first determine the mass loss after heating, which indicates the amount of water evaporated. The initial mass of the mixture is 1.392g, and after heating, it weighs 1.087g, suggesting that the difference (0.305g) is the mass of water lost. This mass loss can help in calculating the weight percent of BaCl2 and BaCl2 * 2H2O in the mixture. The specific value of 8.46507394x10-3 needs clarification regarding its context, as it is unclear what it represents. Understanding the relationship between the compounds and their respective molar masses is essential for accurate calculations.
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If I have BaCl2 *2H2O how does that come to 8.46507394x10-3

Here is the question:
A common laboratory experiment involves the analysis of a mixture of BaCl2 and BaCl2 *2H2O. you are given a white powder that is a mixture of these compounds and are asked to determine the weight percent of each. you find that 1.392g of the mixture has a mass of 1.087g after heating it to drive off all of the water present.
 
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nieuport27 said:
If I have BaCl2 *2H2O how does that come to 8.46507394x10-3

In general - it doesn't, and what you wrote doesn't make sense. 8.46507394x10-3 of what? Cows? Marbles? mph? mpg? Stones per week?

Please note you have to show your attempts at solving the question to receive help. This is a forum policy.

A common laboratory experiment involves the analysis of a mixture of BaCl2 and BaCl2 *2H2O. you are given a white powder that is a mixture of these compounds and are asked to determine the weight percent of each. you find that 1.392g of the mixture has a mass of 1.087g after heating it to drive off all of the water present.

Hint: why did the sample get lighter?
 
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