How Do You Calculate Norton Equivalent Circuits in Electrical Engineering?

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SUMMARY

The discussion focuses on calculating Norton equivalent circuits in electrical engineering, specifically addressing the calculation of Norton resistance (R(n)) and mesh analysis. The user successfully determined R(n) to be 34 ohms by turning off independent sources and analyzing resistors in series. The challenge arises from a 2 amp current source affecting mesh currents, leading to confusion about the values of I2 and I3. The solution involves using mesh equations or superposition to accurately calculate the currents in the circuit.

PREREQUISITES
  • Understanding of Norton equivalent circuits
  • Familiarity with mesh analysis techniques
  • Knowledge of superposition theorem in circuit analysis
  • Basic concepts of series and parallel resistors
NEXT STEPS
  • Study mesh analysis in detail to improve circuit-solving skills
  • Learn about the superposition theorem and its applications in circuit analysis
  • Explore current divider rules for better understanding of current distribution
  • Practice calculating Norton and Thevenin equivalents for various circuits
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing and simplifying electrical circuits using Norton and Thevenin equivalents.

ihavaquestion
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Homework Statement


Find norton equivalent circuit


Homework Equations


Rn=Rth


The Attempt at a Solution


Ok i got my R(n)=34 ohms because after you turn off independent sources the resistors are in series, then I short circuited a to be and I'm trying to use mesh analysis to solve for I(n)
the problem arises with the 2 amp current source does that make I2 and I3 2 amps? help!?
 

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ihavaquestion said:

Homework Statement


Find norton equivalent circuit


Homework Equations


Rn=Rth


The Attempt at a Solution


Ok i got my R(n)=34 ohms because after you turn off independent sources the resistors are in series, then I short circuited a to be and I'm trying to use mesh analysis to solve for I(n)
the problem arises with the 2 amp current source does that make I2 and I3 2 amps? help!?

You can write the mesh equations for the circuit and calculate the current in ab.
Or you can use superposition: cancel one of the current sources and calculate the current, then activate that source and cancel the other. The total sum of the two partial currents. current is the
 
ihavaquestion said:
the problem arises with the 2 amp current source does that make I2 and I3 2 amps? help!?

You didn't label the diagram with mesh currents, so I'll guess that you have three meshes numbered from left to right in the circuit. For clockwise mesh currents i1, i2, i3, the 2A independent source will make i3 - i2 = 2A.

Note that you could also solve the problem pretty easily using superposition: you get a couple of straightforward current dividers to deal with.
 
thank you for your help
 

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