- #1

dcrisci

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Hello, I am dario and have a problem that deals with electrical circuits

I have a practice problem for Nortons and Thevenins equivalents, and don't really know how to approach it. I'm confused when it comes to choosing a load, and reducing it into the final simple circuit.

The problem is i the attached picture provided, it is a drawing of a circuit.

V = IR

Current divider: I

Voltage Divider: V

Thevenins Resistance = Nortons Resistance

Nortons Current = Thevenins Voltage / Thevenins or Nortons Resistance

I do not have any progress really because I do not really know how to approach this circuit. Would i neglect the output on the right because no current will flow there and remove the load R1 to determine the circuit? I don't see how else the circuit could be reduced to a Nortons circuit.

I have a practice problem for Nortons and Thevenins equivalents, and don't really know how to approach it. I'm confused when it comes to choosing a load, and reducing it into the final simple circuit.

## Homework Statement

The problem is i the attached picture provided, it is a drawing of a circuit.

## Homework Equations

V = IR

Current divider: I

_{Rx}= ( R_{total}/ R_{x}) I_{total}Voltage Divider: V

_{Rx}= (R_{x}/ R_{total}) * V_{total}Thevenins Resistance = Nortons Resistance

Nortons Current = Thevenins Voltage / Thevenins or Nortons Resistance

## The Attempt at a Solution

I do not have any progress really because I do not really know how to approach this circuit. Would i neglect the output on the right because no current will flow there and remove the load R1 to determine the circuit? I don't see how else the circuit could be reduced to a Nortons circuit.