How Do You Calculate Relative Error in Mass Measurement?

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To calculate the mass of air in a room with given dimensions and density, the volume is determined as 40 m³, leading to a mass of approximately 0.03 kg. The relative error for the mass is derived from the individual relative errors of the measured quantities. Since the density has a relative error of 5% and each dimension has a 10% relative error, the total relative error for the mass is calculated by adding these errors together. Thus, the relative error for the mass would be 5% + 10% + 10% + 10%, resulting in a total relative error of 35%. Understanding how to combine relative errors is crucial for accurate mass measurement calculations.
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Assume the density of air was measured as 1.00 kg/m3 ± 5%. The room has dimensions 4 m × 5 m × 2 m, each measured with 10% relative error. What is the mass of the air in the room? What is the relative error for the mass?

I think this is a very simple problem, and i found what the mass of the air would be, i just don't understand relative errors, so how do i find the relative error for the mass?

D = m/V D = 1.00 kg/m3 V = (4 m *5 m *2 m) = 40 m3
m = (1.00 kg/m3)/ (40 m3)
m = .025 kg → m = .03 kg

relative error: Is it something like 5%/ 10% ??
 
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Have you studied the rule for how to get the relative error when you multiply two quantities?
 
no, we didn't learn much about relative error at all.
 
Have a look at this page:

http://www.rit.edu/~uphysics/uncertainties/Uncertaintiespart2.html

I myself don't know that much about how to treat relative errors... but it seems like when you multiply quantities you add relative errors.

In your calculation there are 4 quantities being multiplied. density, length, width, height... so I'm guessing you just add the relative errors to get the relative error of the mass...
 
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