How Do You Calculate the Density of a Partially Submerged Sphere?

AI Thread Summary
To calculate the density of a partially submerged sphere, apply Archimedes' Principle, which states that the weight of the displaced water equals the weight of the object. The volume of the immersed part of the sphere can be determined using integration, yielding a volume of 9πR³/8. This leads to the density of the sphere being 27/32 times the density of water. While there are alternative methods, such as using hydrostatic pressure, the initial approach is valid and correct. Understanding the relationship between buoyant force and displaced fluid weight is key to solving the problem.
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Homework Statement


a sphere of uniform density and radius R is floating on water , partially immersed such that the distance between the top of the sphere and the water surface is R/2
find the density of the sphere

Homework Equations


Archimedes Principle

The Attempt at a Solution


One can deduce from the Archimedes Principle ,that the weight of the displaced water = the weight of the object

ρWaterVDisplaced waterg=ρObject VObjectg

which basically turns the problem into a mathematical problem involving finding the volume of the immersed part of the sphere.

Consider a circle of radius R centered at the origin ,

the required volume is ∫π(R2-x2)dx from -R to R/2 = 9πR3/8

Thus , ρObject=(9πR3/8)/(4πR3/3) * ρWater

=27/32 ρWaterI don't know if it's a legitimate method . It is suggested that I utilize the concept of hydrostatic pressure instead , but i have no idea how to do that.[/SUB]
 
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It is legitimate and correct. The buoyant force is equal to the weight of the displaced fluid.
 
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