How Do You Calculate the Distance Traveled in the Last Second of Acceleration?

AI Thread Summary
To calculate the distance traveled during the twelfth second of a plane's acceleration, the first equation of motion can be used. The plane moves 600 meters in 12 seconds, allowing for the determination of its position at the end of the 11th second and the end of the 12th second. By finding the difference between these two positions, the distance traveled in the last second can be accurately calculated. The user expresses frustration in solving this part of the problem, indicating a need for clarification on the application of the equations. Understanding the correct use of the equations is essential for solving the problem effectively.
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Homework Statement



A plane starts from rest and accelerates in a straight line along the ground before takeoff. It moves 600m in 12s. Find a) acceleration, b) speed at the end of 12s, c) the distance moved during the twelfth second.

Homework Equations


d = vot + 1/2at^2

v = vot + at


The Attempt at a Solution



I got the answers to part a and b, but not to part c. I feel stupid, I've been staring at this part for awhile. Things are not registering...:frown:

Do i use the first equation?

someone please help!
 
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This is the distance traveled during one second between t1=11 s and t2=12 s time. You can use the first equation to get where was the plane at the end of the 11th second and where is it at the end of the 12th second. ehild
 
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