How Do You Calculate the Force of Tension in a Pendulum Rope?

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To calculate the force of tension in a pendulum rope, consider both the gravitational force and the centripetal force acting on the bowling ball at its lowest point. The tension in the rope (FT) must counteract the weight of the ball (mg) and provide the necessary centripetal force (mv²/R). The equation to use is FT = mg + mv²/R, where m is the mass of the ball, v is its speed, and R is the length of the rope. The acceleration calculated at 4.74 m/s² is relevant for determining the net forces involved. Properly applying these concepts will yield the correct tension in the rope.
enantiomer1
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A bowling ball weighing 71.2 N is attached to the ceiling by a 3.90 m rope. The ball is pulled to one side and released; it then swings back and forth like a pendulum. As the rope swings through its lowest point, the speed of the bowling ball is measured at 4.30 m/s

I've figured out that acceleration = 4.74 m/s2
Now all I need to know is the force of tension in the rope , I've tried FT= ma
but that isn't working so I'm stuck
anyone know what equation I'm missing?
 
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If the question is what is the tension of the rope at the lowest point, then you should be thinking in terms of both mg and mv2/R.
 
enantiomer1 said:
I've tried FT= ma
but that isn't working so I'm stuck
That would work if Ft was the only force acting on the ball, but it's not. Set the net force equal to ma.
 
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