How Do You Calculate the Load on a Prop Between Two Cantilever Beams?

AI Thread Summary
To calculate the load on a prop between two cantilever beams, one can start by subtracting the deflections of the beams at the free ends to determine the elongation of the prop. Using the initial length of the prop and the calculated stretch, the strain can be found, which, along with Young's modulus, allows for the calculation of stress. The stress can then be used to find the force on the prop using the formula σ=F/A. It's important to ensure that the signs of the deflections are correct, as this can affect the calculations significantly. Overall, this method provides a plausible approach to solving the problem.
phiska
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If i have two cantilever beams with a vertical prop between the free ends as shown in diagram, how do i find the load on the prop?

I have the deflections of the beams to be:

v (top beam)= (PL^3)/(3EI)
v(bottom beam)=(5WL^3)/(48EI)-(PL^3)/(3EI)

the prop is of diameter d, and length a, with youngs modulus E.

Any hints/help appreciated!
 

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I have been seeing you over here doing such questions. When we try to answer you, suddenly you disappear and never return to the thread for replying something.

Be a bit more polite and take into consideration the people who helps you.
 
I'm sorry, do not intend to appear rude.

I am very grateful to everyone who takes the time to help me.
 
This is totally just a guess...but...

Subtract your two deflections at the end of the cantilever to find out the elongation of the "prop." Given the initial length and the stretch, you can easily find the strain on the prop. Given strain and Modulus of Elasticity, you can now find stress. Given stress, and cross sectional area, you can solve σ=F/A for F, force.

This is just what I would try, and it is not guarenteed to work...seems like it would though.

edit: What is P by the way? Also, make sure the signs on your deflections are correct. If one of the PL.. terms was opposite, then when you subtracted the deflections, they would cancel each other out, making the problem significantly easier. That is, unless You need to add the deflections for some reason (maybe your deflections are poining in different directions).
 
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That definitely sounds like a plausible solution.

I will have a go and see if it works out, and will let you know.

Thanks a lot
 
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