How Do You Calculate the Mass of a Cone Using Volume Integrals?

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implet
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Homework Statement


"A solid cone is bounded by the surface [tex]\theta=\alpha[/tex] in spherical polar coordinates and the surface [tex]z=a[/tex]. Its mass density is [tex]p_0\cos(\theta)[/tex]. By evaluating a volume integral find the mass of the cone.


Homework Equations





The Attempt at a Solution


I can't figure out the correct limits for the volume integral. Is it best to solve in Cartesian or spherical polar coordinates?

Many thanks :)
 
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implet said:

Homework Statement


"A solid cone is bounded by the surface [tex]\theta=\alpha[/tex] in spherical polar coordinates and the surface [tex]z=a[/tex]. Its mass density is [tex]p_0\cos(\theta)[/tex]. By evaluating a volume integral find the mass of the cone.
Your description of the cone suggests your interpretation of spherical polar coordinates is [tex](r, \theta, \phi)[/tex] where [tex]\theta[/tex] is the angle from the positive z-axis and [tex]\phi[/tex] is the angle from the positive x-axis.

We look to use these coordinates to calculate the integral for the cone. Sketch the cone: it makes an angle of alpha with the positive z-axis and goes up to z=a. More specifically...

[tex]\theta[/tex] runs from [tex]0[/tex] to [tex]\alpha[/tex].

[tex]\phi[/tex] goes from ... to ... ?

To find the r-limits, draw a right-angled triangle:
Code:
   -----
   |   /
 a |  / r      where A is the angle alpha. 
   |A/
   |/
.