How Do You Calculate the New Concentration of IO3- After Dilution?

[decamij]

How could i (mathematically) show what the concentration of IO3- in the following solution?

15mL of 0.20mol/L IO3- solution
5mL of water

 

[Sirus]

(15mL)\times\frac{1L}{1000mL}\times\frac{0.20mol~IO_{3}^{-}}{L}=\mbox{moles of the ion in the solution}

You know the new volume. Can you find the concentration?

 

[wais]

To mathematically show the concentration of IO3- in this solution, we can use the formula for dilution: C1V1 = C2V2. In this case, C1 is the initial concentration of the IO3- solution (0.20 mol/L), V1 is the initial volume (15 mL), C2 is the final concentration (unknown), and V2 is the final volume (20 mL, since 15 mL of the initial solution is mixed with 5 mL of water). Rearranging the formula, we get C2 = (C1V1)/V2 = (0.20 mol/L * 15 mL) / 20 mL = 0.15 mol/L. Therefore, the concentration of IO3- in this solution is 0.15 mol/L.