How Do You Calculate the Oscillation Period and Energy Gain in an LC Circuit?

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Homework Help Overview

The discussion revolves around an oscillating LC circuit, focusing on calculating the period of oscillation and the maximum energy gain of the inductor. The original poster provides specific parameters such as current amplitude, potential amplitude, and capacitance, and poses two questions related to these calculations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between energy stored in the inductor and its maximum rate of energy gain. There are attempts to derive equations for energy and current, with some questioning the accuracy of the original poster's calculations and assumptions regarding the charge (Q).

Discussion Status

The discussion is ongoing, with participants providing insights and corrections regarding the equations used. Some participants have expressed confusion about the definitions and calculations involved, while others are clarifying concepts related to energy in the circuit.

Contextual Notes

There is mention of potential misunderstandings regarding the equations for energy and charge in the circuit, indicating that participants are grappling with the underlying physics concepts. The original poster has acknowledged previous errors and is seeking further clarification.

Oijl
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Homework Statement


An oscillating LC circuit has a current amplitude of 7.20 mA, a potential amplitude of 250 mV, and a capacitance of 240 nF.

(a) What is the period of oscillation?

(e) What is the maximum rate at which the inductor gains energy?

Homework Equations


Possibly: Energy stored in an inductor = 1/2 * L * I^2
i = -wQsin(wt+ø)

The Attempt at a Solution


Energy per unit of time is Watts.

If I find the equation for energy stored in an inductor, I can differenceate that with respect to time and find its maximum value.

I thought that this would be:
dE/dt = P = -L(w^3)(Q^2)sin(wt)cos(wt)

And isn't the maximum value for this just

(1/2)L(w^3)(Q^2) ?

And isn't that just

0.9 mW ?

I've done this problem wrong several times so far, so is this one right?
 
Last edited:
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U = ((Q^2)/2C) cos(^2)(wt+ø) is the equation for the energy contained in the capacitor,
not for the potential across it.
 
How are you determining Q? I get Q = VC = .25 *2.4e(-7) = 6e(-8) C.

Q = VC = \int_0^{\pi/2} dQ = \int_0^{\pi/2} idt = \int_0^{\pi/2} i_{max}\sin{\omega t}dt

so:

Q = VC = i_{max}/\omega



AM
 
Oh, I see. I misunderstood the equation for U I had written, and therefore got a bad Q. Thanks to both.
 
But now I have another question for this problem, and I've edited the first post for it.
 

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