How Do You Calculate the Potential Difference in a Parallel Plate Capacitor?

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To calculate the potential difference across a parallel plate capacitor, the formula V = Q / (ε₀ * A / d) is used, where Q is the charge, ε₀ is the permittivity of free space, A is the area, and d is the distance between the plates. The area should be converted correctly to 0.000477 m², and the distance should be 0.00106 m. The dielectric constant for air is approximately 1, and the charge is given as 403 pC. After substituting the correct values into the formula, the calculated potential difference should be verified for accuracy. The initial calculation of 1.01V was incorrect due to an area conversion error.
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A parallel-plate capacitor has an area of 4.77 cm2, and the plates are separated by 1.06 mm with air between them. It stores a charge of 403 pC. What is the potential difference across the plates of the capacitor?

alright so i changed the area to .0477m^2. then i changed the distance between the plates to .00106m. i used 1.00054 as the dielectric constant. and i changed the charge to 403E-12C.

then i took 403E-12=((1.00054)(8.85E-12)(.0477)/(.00106))V

and i get V to equal 1.01V and its wrong. any help is appreciated.
 
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For one thing, 4.77 cm^2 is 0.000477 m^2.
 

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